10th Class Mathematics Related to Competitive Exam Question Bank Quadratic Inequation

  • question_answer
    The value of a which make the expression \[{{x}^{2}}-ax+1-2{{a}^{2}}\] always positive for real values of x, are

    A)  \[-\frac{4}{3}<a<\frac{4}{3}\]            

    B)  \[-\frac{2}{3}<a<\frac{2}{3}\]

    C)  \[a\in \]null set              

    D)  \[0<a<\frac{7}{3}\]

    Correct Answer: B

    Solution :

    (b): Since the coefficient of \[{{x}^{2}}\] is 1 which is positive, therefore the given expression is positive for all real values of x if D < 0, therefore the given expression is positive for all real values of x if D<0. \[\Rightarrow {{\left( -a \right)}^{2}}-4\left( 1-2{{a}^{2}} \right)<0\]        \[\Rightarrow 9{{a}^{2}}-4<0\] \[\Rightarrow \left( 3a+2 \right)\left( 3a-2 \right)<0\]                        \[\Rightarrow -\frac{2}{3}<a<\frac{2}{3}\]


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