A) \[x<3/2\]or \[x>7/3\]
B) \[3/2<x<7/3\]
C) \[x>7/3\]
D) None of these
Correct Answer: A
Solution :
(a): \[\frac{2x-3}{3x-7}>0\Rightarrow \frac{\left( x-\frac{3}{2} \right)}{\left( x-\frac{7}{3} \right)}>0\] and proceed to solve. (If required, see the procedure solution to question 36 for reference)
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