10th Class Mathematics Quadratic Equations Question Bank Quadratic Equations

  • question_answer
    A man walks a distance of 48 km in a given time. If he walks 2 km/hr faster, he will perform the journey 4 hrs before. His; normal rate of walking, is _____.    

    A)  3 km/hr        

    B)                     4 km/hr     

    C)                     - 6 km/hr or 4 km/hr             

    D)                     5 km/hr                        

    Correct Answer: B

    Solution :

    Let the speed of man be x km/hr and the time taken by him to cover 48 km with speed x be t. According to the question,\[48=x\times t\]        ...(1) Also,  \[48=(x+2)\,(t-4)\]                    ....(2) \[\Rightarrow \]     \[48=xt-4x+2t-8\]        \[\Rightarrow \]            \[56=48-4x+2t\]   [Using (1)] \[\Rightarrow \]     \[8=-4x+2t\] \[\Rightarrow \] \[4=-2x+t\] \[\Rightarrow \]            \[4=-2x+\frac{48}{x}\]     [Using (1)] \[\Rightarrow \]\[2x=-{{x}^{2}}+24\] \[\Rightarrow \] \[{{x}^{2}}+2x-24=0\] \[\Rightarrow \] \[x=\frac{-2\pm \sqrt{4+96}}{2}=4\]  or  \[-6\] Since, speed cannot be negative. Required speed is \[4\text{ }km/hr\]


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