A) \[{{x}^{2}}-12x+30=0\]
B) \[{{x}^{2}}-12x+32=0\]
C) \[2{{x}^{2}}-6x+7=0\]
D) \[2{{x}^{2}}-24x+43=0\]
Correct Answer: B
Solution :
Let the two roots be a and b, then \[a+b=12\] ...(1) and \[a-b=4\] ...(2) \[\Rightarrow \] \[a=8\]and \[b=4\](from (1) and (2)) Required equation is\[{{x}^{2}}-12x+32=0\]You need to login to perform this action.
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