A) \[{{x}^{2}}+6x-3=0\]
B) \[{{x}^{2}}-6x-3=0\]
C) \[{{x}^{2}}+6x+3=0\]
D) \[{{x}^{2}}-6x+3=0\]
Correct Answer: B
Solution :
Let\[={{\text{2}}^{\text{6}}}\times {{\text{5}}^{\text{2}}}\times {{\text{7}}^{\text{4}}}\text{c}{{\text{m}}^{\text{2}}}\]and \[2-\sqrt{4}=2-2=0\] \[{{(\sqrt{5})}^{2}}=5\] \[\sqrt{9}-\sqrt{4}=3-2=1\] \[\sqrt{2}-\sqrt{3}\]The required quadratic equation is \[1789=29x+49\].
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