A) \[\frac{b}{c}\]
B) \[\frac{c}{2b}\]
C) \[\frac{ab}{c}\]
D) \[\frac{bc}{a}\]
Correct Answer: B
Solution :
(b): \[(a-b)(b-c)=\]product of the roots \[=\frac{c}{a}\] Also \[(c-a)=-\left[ (a-b)+(b-c) \right]\] = ? sum of roots = \[\frac{b}{a}\] \[\Rightarrow \frac{(a-b)(b-c)}{2(c-a)}=\frac{\frac{c}{a}}{\frac{2b}{a}}=\frac{c}{2b}\]You need to login to perform this action.
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