A) ? 3
B) 1
C) 3
D) ? 6
Correct Answer: B
Solution :
(b): \[\left( {{p}^{2}}-{{q}^{2}} \right){{u}^{2}}+\left( {{q}^{2}}-{{r}^{2}} \right)u+\left( {{r}^{2}}-{{p}^{2}} \right)=0\] The sum of the coefficients \[\left( {{p}^{2}}-{{q}^{2}} \right){{u}^{2}}+\left( {{q}^{2}}-{{r}^{2}} \right)u+\left( {{r}^{2}}-{{p}^{2}} \right)=0\] \[\therefore u=1\]is a root of Eq. (1) \[\left( {{p}^{2}}-{{q}^{2}} \right){{v}^{2}}+\left( {{r}^{2}}-{{p}^{2}} \right)v+{{q}^{2}}-{{r}^{2}}=0\] \[{{p}^{2}}-{{q}^{2}}+{{r}^{2}}-{{p}^{2}}+{{q}^{2}}-{{r}^{2}}=0\] \[\therefore v=1\]is a root of Eq. (2) \[\therefore 1\] is the common root of Eq. (1) and (2).You need to login to perform this action.
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