A) Ethene
B) Ethyne
C) 2-butene
D) 1-butene
Correct Answer: C
Solution :
\[C{{H}_{3}}CH<\begin{matrix} Br \\ Br \\ \end{matrix}+4Na+\begin{matrix} Br \\ Br \\ \end{matrix}>CH-C{{H}_{3}}\underset{\Delta }{\mathop{\xrightarrow{\text{ether}}}}\,\]\[\underset{\text{2-butene}}{\mathop{C{{H}_{3}}-CH=CH-C{{H}_{3}}}}\,+4NaBr\]You need to login to perform this action.
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