A) Friedal-Craft reaction
B) Hofmann degradation
C) Kolbe's synthesis
D) Beckmann rearrangement
Correct Answer: A
Solution :
Acylation or alkylation of aromatic compound in presence of \[AlC{{l}_{3}}\] is known as Friedal-craft reaction. \[\underset{\text{Benzene}}{\mathop{{{C}_{6}}{{H}_{6}}}}\,+\underset{\begin{smallmatrix} \text{chloro} \\ \text{methane} \end{smallmatrix}}{\mathop{C{{H}_{3}}Cl}}\,\underset{AlC{{l}_{3}}}{\mathop{\xrightarrow{\text{dry}}}}\,\underset{\text{Toluene}}{\mathop{{{C}_{6}}{{H}_{5}}C{{H}_{3}}}}\,+HCl\]
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