A) 2-chloropropane and chloromethane
B) 2-chloropropane and chloroethane
C) Chloromethane and chloroethane
D) Chloromethane and 1-chloropropane
Correct Answer: A
Solution :
It is Wurtz reaction in which hydrocarbon formed when alkyl halide react with Na metal in dry ether. \[\underset{\text{2 chloro propane}}{\mathop{C{{H}_{3}}-\overset{Cl\ }{\mathop{\overset{|}{\mathop{C}}\,H}}\,-C{{H}_{3}}}}\,+\underset{\begin{smallmatrix} \text{chloro} \\ \text{methane} \end{smallmatrix}}{\mathop{C{{H}_{3}}Cl}}\,+2Na\xrightarrow{\text{ether}}\] \[\underset{\text{2 methyl propane}}{\mathop{C{{H}_{3}}-\overset{C{{H}_{3}}\ }{\mathop{\overset{|}{\mathop{C}}\,H-}}\,C{{H}_{3}}+2NaCl}}\,\]
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