A) 1-bromo-2, 2-dimethylpropane
B) 1-bromobutane
C) 1-bromo-2-methylbutane
D) 2-bromo-2-methylbutane
E) 2-bromopentane
Correct Answer: C
Solution :
\[\underset{\text{1, bromo, 2 methyl butane}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-\overset{C{{H}_{3}}\,}{\mathop{\overset{|}{\mathop{C}}\,H-}}\,C{{H}_{2}}Br}}\,+{{C}_{2}}{{H}_{5}}ONa\xrightarrow{{{C}_{2}}{{H}_{5}}OH}\] \[C{{H}_{3}}-C{{H}_{2}}-\overset{C{{H}_{3}}\ \ \ \ \ \,}{\mathop{\overset{|}{\mathop{C}}\,=C{{H}_{2}}}}\,+NaBr+{{C}_{2}}{{H}_{5}}OH\underset{\text{(Hydrogenation)}}{\mathop{\xrightarrow{+{{H}_{2}}}}}\,\] \[\underset{\text{2 methyl butane}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-\overset{C{{H}_{3}}\,}{\mathop{\overset{|}{\mathop{C}}\,H-}}\,C{{H}_{3}}}}\,\]
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