A) \[CHC{{l}_{3}}+AgN{{O}_{3}}\]
B) \[CHC{{l}_{3}}+{{O}_{2}}\]
C) \[CHC{{l}_{3}}+HN{{O}_{3}}\]
D) \[CHC{{l}_{3}}+Ag\]
Correct Answer: D
Solution :
\[CHC{{l}_{3}}+6Ag+C{{l}_{3}}CH\to CH\equiv CH+6AgCl\]
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