A) Chloral
B) \[CHC{{l}_{3}}\]
C) \[C{{H}_{3}}Cl\]
D) Chloroacetic acid
Correct Answer: A
Solution :
\[\underset{A}{\mathop{{{C}_{2}}C{{l}_{3}}OH}}\,+\text{Fehling}\,\text{sol}\text{.}\to \underset{\text{Red}\ \text{ppt}}{\mathop{C{{u}_{2}}O}}\,\] It means -CHO group is present. \[\underset{A}{\mathop{{{C}_{2}}C{{l}_{3}}OH}}\,\xrightarrow{\text{Oxidation}}\underset{\text{Monocarboxylic}\,\,\text{acid}}{\mathop{CC{{l}_{3}}-COOH}}\,\] It means only one -CHO group is present. \[{{C}_{2}}{{H}_{5}}OH+C{{l}_{2}}\to C{{H}_{3}}CHO+2HCl\] \[C{{H}_{3}}CHO+3C{{l}_{2}}\to \underset{\text{Chloral}}{\mathop{CC{{l}_{3}}CHO}}\,+3HCl\]
You need to login to perform this action.
You will be redirected in
3 sec
