A) \[{{C}_{2}}{{H}_{5}}Br\] reacts with alco. KOH to form \[{{C}_{2}}{{H}_{5}}OH\]
B) \[{{C}_{2}}{{H}_{5}}Br\] when treated with metallic sodium gives ethane
C) \[{{C}_{2}}{{H}_{5}}Br\] when treated with sodium ethoxide forms diethyl ether
D) \[{{C}_{2}}{{H}_{5}}Br\] with AgCN forms ethyl isocyanide
Correct Answer: A
Solution :
\[{{C}_{2}}{{H}_{5}}Br+alc\text{.}K\text{OH}\to {{C}_{2}}{{H}_{4}}+{{H}_{2}}O+KBr\] \[+Br-{{C}_{2}}{{H}_{5}}\to \underset{\text{Butane}}{\mathop{{{C}_{2}}{{H}_{5}}-{{C}_{2}}{{H}_{5}}}}\,+2NaBr\]
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