A) 2
B) ?1
C) 1
D) ? 2
Correct Answer: C
Solution :
The sum of the coefficients of the polynomial \[{{({{\alpha }^{2}}{{x}^{2}}-2\alpha \,x+1)}^{51}}\]is obtained by putting \[x=1\] in \[{{({{\alpha }^{2}}{{x}^{2}}-2\alpha \,x+1)}^{51}}\]. Therefore by hypothesis \[{{({{\alpha }^{2}}-2\alpha +1)}^{51}}=0\Rightarrow \alpha =1\]
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