A) \[(n+2){{2}^{n-1}}\]
B) \[(n+1){{2}^{n}}\]
C) \[(n+1){{2}^{n-1}}\]
D) \[(n+2){{2}^{n}}\]
Correct Answer: A
Solution :
Trick: Put n=1, the expression is equivalent to \[^{1}{{C}_{0}}+{{2.}^{1}}{{C}_{1}}=1+2=3\] Only option (a) gives the value.
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