A) \[C{{H}_{3}}OH\]
B) \[{{C}_{2}}{{H}_{5}}OH\]
C) \[C{{H}_{3}}COOH\]
D) HCHO
Correct Answer: C
Solution :
\[C{{H}_{3}}-C\,<-\begin{matrix} OH \\ OH \\ OH \\ \end{matrix}\to C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-OH+{{H}_{2}}O\] If two or more \[-OH\] groups are present on carbon atom then it immediately looses water molecule and forms acid or aldehyde. Two\[-OH\]groups on the same carbon aldehyde is formed \[\underset{\text{Unstable}}{\mathop{R-CH<\begin{matrix} OH \\ OH \\ \end{matrix}}}\,\xrightarrow[-{{H}_{2}}O]{}\underset{\text{Aldehyde}}{\mathop{R-\underset{\underset{H}{\mathop{|}}\,}{\mathop{C}}\,=O}}\,\] Three \[-OH\] groups on the same carbon acid is formed. \[R-C<-\begin{matrix} OH \\ OH \\ OH \\ \end{matrix}\xrightarrow[-{{H}_{2}}O]{}R-C<\underset{\text{acid}}{\mathop{\,\,\,\,\,\begin{matrix} OH \\ O\,\,\, \\ \end{matrix}}}\,\]
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