A) Ethane
B) Ethylene
C) Butane
D) Propane
Correct Answer: A
Solution :
\[{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}\underset{\begin{smallmatrix} \text{Cleavage}\,\text{of} \\ \text{ }\,\text{ethers} \end{smallmatrix}}{\mathop{\xrightarrow{\text{Red}\,P/HI}}}\,2{{C}_{2}}{{H}_{5}}I\]\[\underset{\text{Reduction}}{\mathop{\xrightarrow{\text{Red}\,P/HI}}}\,\underset{\text{Ethane}}{\mathop{2{{C}_{2}}{{H}_{6}}}}\,\]
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