A) Methyl > ethyl > iso-propyl > tert-butyl
B) Tert-butyl > iso-propyl > ethyl > methyl
C) Iso-propyl > tert-butyl > ethyl > methyl
D) Tert-butyl > ethyl > iso-propyl > methyl
Correct Answer: B
Solution :
\[\underset{{{3}^{o}}}{\mathop{C{{H}_{3}}-\begin{array}{*{35}{l}} C{{H}_{3}} \\ \underset{|\,\,\,}{\overset{|\,\,\,}{\mathop{{{C}^{+}}}}}\, \\ C{{H}_{3}} \\ \end{array}}}\,>\underset{\begin{smallmatrix} \, \\ \\ {{2}^{o}} \end{smallmatrix}}{\mathop{C{{H}_{3}}-\overset{+}{\mathop{C}}\,H}}\,>\underset{\begin{smallmatrix} \\ \, \\ {{1}^{o}} \end{smallmatrix}}{\mathop{C{{H}_{3}}\overset{+}{\mathop{C}}\,{{H}_{2}}}}\,>\underset{\begin{smallmatrix} \, \\ \text{Methyl} \\ \text{Carbonium ion} \end{smallmatrix}}{\mathop{\overset{+}{\mathop{C}}\,{{H}_{3}}}}\,\]
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