A) Protonation of alcohol molecule
B) Formation of carbocation
C) Elimination of water
D) Formation of an ester
Correct Answer: A
Solution :
\[{{H}_{2}}S{{O}_{4}}\to {{H}^{+}}+HSO_{4}^{-}\] \[{{C}_{2}}{{H}_{5}}OH+{{H}^{+}}\underset{\text{of}\,\,\text{alcohol}}{\mathop{\xrightarrow{\text{Protonation}}}}\,\underset{\text{Protonated alcohol}}{\mathop{{{C}_{2}}{{H}_{5}}-\underset{H}{\mathop{\underset{\downarrow }{\overset{\oplus }{\mathop{O}}}\,}}\,-H}}\,\]
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