JEE Main & Advanced Physics Wave Mechanics Question Bank Progressive Waves

  • question_answer
    A transverse wave is given by \[y=A\sin 2\pi \left( \frac{t}{T}-\frac{x}{\lambda } \right)\]. The maximum particle velocity is equal to 4 times the wave velocity when [MP PMT 2001]

    A)            \[\lambda =2\pi A\]          

    B)            \[\lambda =\frac{1}{2}\pi A\]

    C)            \[\lambda =\pi A\]            

    D)            \[\lambda =\frac{1}{4}\pi A\]

    Correct Answer: B

    Solution :

               Given \[A\omega =4v\Rightarrow A2\pi n=4n\lambda \Rightarrow \lambda =\frac{\pi A}{2}\]


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