A) \[v=5\,m/\sec \]
B) \[\lambda =18\,m\]
C) \[a=0.04\,m\]
D) \[n=50\,Hz\]
Correct Answer: B
Solution :
From the given equation amplitude \[a=0.04m\] Frequency \[=\frac{\text{Co}-\text{efficient of t}}{2\pi }\]\[=\frac{\pi /5}{2\pi }=\frac{1}{10}Hz\] Wave length \[\lambda =\frac{2\pi }{\text{Co}-\text{efficient}\ of\ x}\] \[=\frac{2\pi }{\pi /9}\]=18m. Wave speed \[v=\frac{\text{Co-efficient of }t}{\text{Co-efficient of }x}\] \[=\frac{\pi /5}{\pi /9}=1.8m/s.\]
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