A) \[100\,Hz,\ 4.7\times {{10}^{3}}\,cm/{{s}^{2}}\]
B) \[50\,Hz,\ 7.5\times {{10}^{3}}\,cm/{{s}^{2}}\]
C) \[25\,Hz,\ 4.7\times {{10}^{4}}\,cm/{{s}^{2}}\]
D) \[25\,Hz,\ 7.4\times {{10}^{4}}\,cm/{{s}^{2}}\]
Correct Answer: D
Solution :
Comparing the given equation with standard equation \[y=a\sin 2\pi \,\left( \frac{t}{T}-\frac{x}{\lambda } \right)\]Þ T = 0.04 sec Þ \[\nu =\frac{1}{T}=25Hz\] Also \[{{(A)}_{\max }}={{\omega }^{2}}a={{\left( \frac{2\pi }{T} \right)}^{2}}\times a={{\left( \frac{2\pi }{0.04} \right)}^{2}}\times 3\] =7.4 ´ 104 cm/sec2.
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