A) 63 cm/s
B) 75 cm/s
C) 100 cm/s
D) 121 cm/s
Correct Answer: A
Solution :
The given equation is \[y=10\sin (0.01\pi x-2\pi t)\] Hence \[\omega =\]coefficient of t = 2p Þ Maximum speed of the particle \[{{v}_{\max }}=a\omega =10\times 2\pi \] = 10 ´ 2 ´ 3.14 = 62.8 » 63 cm/s
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