A) \[y(x,\,t)=0.5\sin (2\pi x-4\pi t)\]
B) \[y(x,\,t)=0.5\cos (2\pi x+4\pi t)\]
C) \[y(x,\,t)=0.5\sin (\pi x-2\pi t)\]
D) \[y(x,\,t)=0.5\cos (2\pi x+2\pi t)\]
Correct Answer: B
Solution :
\[\because \] \[y=a\cos \left( \frac{2\pi }{\lambda }vt+\frac{2\pi x}{\lambda } \right)=0.5\cos \left( 4\pi t+2\pi x \right)\]
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