A) \[3{{x}^{2}}+4{{y}^{2}}=192\]
B) \[4{{x}^{2}}+3{{y}^{2}}=192\]
C) \[{{x}^{2}}+{{y}^{2}}=192\]
D) None of these
Correct Answer: A
Solution :
\[\sqrt{{{(h-4)}^{2}}+{{k}^{2}}}=\frac{1}{2}\left( \frac{h-16}{\sqrt{{{1}^{2}}+0}} \right)\] Replace \[(h,k)\] by\[(x,\,y)\], we get \[3{{x}^{2}}+4{{y}^{2}}=192.\]
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