A) \[21x-77y+153=0\]
B) \[99x+77y-133=0\]
C) \[7x-11y=19\]
D) None of these
Correct Answer: B
Solution :
Let point be \[({{x}_{1}},{{y}_{1}}),\]then according to the condition \[\frac{3{{x}_{1}}+4{{y}_{1}}-11}{5}=-\left( \frac{12{{x}_{1}}+5{{y}_{1}}+2}{13} \right)\] Since the given lines are on opposite sides with respect to origin, hence the required locus is \[99x+77y-133=0\] .
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