A) Isosceles
B) Equilateral
C) Right?angled
D) None of these
Correct Answer: A
Solution :
The vertices of triangle are the intersection points of these given lines. The vertices of \[\Delta \] are \[A(0,\,4),\] \[B(1,2),\]\[C(4,0)\] Now, \[AB=\sqrt{{{(0-1)}^{2}}+{{(4-1)}^{2}}}=\sqrt{10}\] \[BC=\sqrt{{{(1-4)}^{2}}+{{(0-1)}^{2}}}=\sqrt{10}\] \[AC=\sqrt{{{(0-4)}^{2}}+{{(0-4)}^{{}}}}=4\sqrt{2}\] \[\because AB=BC\]; \ D is isosceles.
You need to login to perform this action.
You will be redirected in
3 sec
