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JEE Main & Advanced Mathematics Straight Line Question Bank Problems related to triangle and quadrilateral Locus

  • question_answer
    The equation to the sides of a triangle are \[x-3y=0\], \[4x+3y=5\] and \[3x+y=0\]. The line \[3x-4y=0\]passes through [EAMCET 1994]

    A)            The incentre

    B)            The centroid

    C)            The circumcentre                      

    D)            The orthocentre of the triangle

    Correct Answer: D

    Solution :

               Two sides \[x-3y=0\]and \[3x+y=0\]of the given triangle are perpendicular to each other. Therefore its orthocentre is the point of intersection of \[x-3y=0\] and \[3x+y=0\] i.e, (0, 0). Clearly (0,0) satisfies \[3x-4y=0\].


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