A) \[\frac{2}{11}\]
B) \[\frac{3}{11}\]
C) \[\frac{6}{11}\]
D) \[\frac{5}{11}\]
Correct Answer: C
Solution :
(c): It will be a pen and a pencil in two ways: 1. P (first pen, then pencil) \[=\frac{5}{11}\times \frac{6}{10}\] 2. P (first pencil, then pen) \[=\frac{6}{11}\times \frac{5}{10}\] \[\therefore \] Required \[P=\frac{5\times 6}{110}+\frac{6\times 5}{110}=\frac{6}{11}\]
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