• # question_answer When two dice are thrown, the probability of getting a number always greater than 4 on the second dice is ___. A)  $\frac{1}{6}$                       B)  $\frac{1}{3}$                       C)  $\frac{1}{36}$                     D)  $\frac{5}{36}$

Total number of outcomes when two dice are thrown = 36. Let A be the event of getting a number always greater than 4 on second dice. $\therefore$ $A=\{(1,5),(1,6),\,(2,5),(2,6),(3,5),(3,6)$ $(4,5),(4,6),(5,5),(5,6),(6,5),(6,6)\}$ $\therefore$    Number of possible outcomes =12 $\therefore$    $P(A)=\frac{12}{36}=\frac{1}{3}$