A) \[0.45\]
B) \[0.98\]
C) \[0.57\]
D) \[0.85\]
Correct Answer: B
Solution :
Out of 600 electric bulbs one bulb can be chosen in 600 ways. \[\therefore \] Total number of elementary events = 600 There are 588 \[(=600-12)\] non-defective bulbs out of which one bulb can be chosen in 588 ways. \[\therefore \] Favorable number of elementary events = 588 Hence, P (Getting a non-defective bulb) \[=\frac{588}{600}\,=\frac{49}{50}\,=0.98\]
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