10th Class Mathematics Probability Question Bank Probability

  • question_answer Two dice are thrown simultaneously. The probability of getting a doublet or a total of 4 is ___.

    A)  \[\frac{2}{9}\]                       

    B)  \[\frac{3}{7}\]           

    C)  \[\frac{4}{9}\]                       

    D)  \[\frac{5}{9}\]

    Correct Answer: A

    Solution :

    Total number of outcomes, when two dice are thrown \[=6\times 6=36\] Total number of doublets present = (1, 1), (2, 2), (3, 3), (4,4). (5, 5), (6, 6) For a total of 4, pairs can be (1, 3), (3, 1), (2, 2). Thus, total number of favourable outcomes = 8 [since (2, 2) is present in both the cases], \[\therefore \] Required probability \[=\frac{8}{36}=\frac{2}{9}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner