10th Class Mathematics Probability Question Bank Probability

  • question_answer Find the probability of getting 53 Fridays in a leap year.

    A)  \[\frac{3}{7}\]                       

    B)  \[\frac{4}{7}\]                       

    C)  \[\frac{2}{7}\]                       

    D)  \[\frac{5}{7}\]                       

    Correct Answer: C

    Solution :

    Leap year contains 366 days. 52 weeks + 2 days 52 weeks contain 52 Fridays. We will get 53 Fridays if one of the remaining two days is a Friday. Total possibilities for two days are: (Sunday, Monday), (Monday, Tuesday), (Tuesday, Wednesday), (Wednesday, Thursday), (Thursday, Friday), (Friday, Saturday), (Saturday, Sunday) There are 7 possibilities and out of these 2 are favorable cases. \[\therefore \]  Required probability \[=\frac{2}{7}\]


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