• # question_answer Find the probability of getting 53 Fridays in a leap year. A)  $\frac{3}{7}$                       B)  $\frac{4}{7}$                       C)  $\frac{2}{7}$                       D)  $\frac{5}{7}$

Leap year contains 366 days. 52 weeks + 2 days 52 weeks contain 52 Fridays. We will get 53 Fridays if one of the remaining two days is a Friday. Total possibilities for two days are: (Sunday, Monday), (Monday, Tuesday), (Tuesday, Wednesday), (Wednesday, Thursday), (Thursday, Friday), (Friday, Saturday), (Saturday, Sunday) There are 7 possibilities and out of these 2 are favorable cases. $\therefore$  Required probability $=\frac{2}{7}$