A) Action of \[N{{H}_{3}}\] on ethyl iodide
B) Action of \[N{{H}_{3}}\] on ethyl alcohol
C) Both A and B
D) None of the above
Correct Answer: C
Solution :
\[{{C}_{2}}{{H}_{5}}I+N{{H}_{3}}\to HI+{{C}_{2}}{{H}_{5}}-N{{H}_{2}}\] \[{{C}_{2}}{{H}_{5}}OH+N{{H}_{3}}\to {{H}_{2}}O+{{C}_{2}}{{H}_{5}}-N{{H}_{2}}\]
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