A) \[C{{H}_{3}}CON{{H}_{2}}\]
B) \[C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}\]
C) \[{{C}_{2}}{{H}_{6}}\]
D) \[C{{H}_{3}}NHC{{H}_{3}}\]
Correct Answer: B
Solution :
\[C{{H}_{3}}C\equiv N+4[H]\underset{\text{Reduction}}{\mathop{\xrightarrow{Na+{{C}_{2}}{{H}_{5}}OH}}}\,C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}\]
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