JEE Main & Advanced Chemistry Nitrogen Containing Compounds Question Bank Preparation of Nitrogen Containing Compounds

  • question_answer In the series of reaction \[{{C}_{6}}{{H}_{5}}N{{H}_{2}}\underset{0-5{}^\circ C}{\mathop{\xrightarrow{NaN{{O}_{2}}/HCl}}}\,X\underset{C{{H}_{2}}O}{\mathop{\xrightarrow{HN{{O}_{2}}}}}\,Y+{{N}_{2}}+HCl\] X and Y are respectively [EAMCET 2003]

    A)                 \[{{C}_{6}}{{H}_{5}}-N=N-{{C}_{6}}{{H}_{5}}\,,\,{{C}_{6}}{{H}_{5}}N_{2}^{\oplus }C{{l}^{\Theta }}\]

    B)                 \[{{C}_{6}}{{H}_{5}}N_{2}^{\oplus }C{{l}^{\Theta }},\,{{C}_{6}}{{H}_{5}}-N=N-{{C}_{6}}{{H}_{5}}\]

    C)                 \[{{C}_{6}}{{H}_{5}}N_{2}^{\oplus }C{{l}^{\Theta }},\,{{C}_{6}}{{H}_{5}}N{{O}_{2}}\]

    D)                 \[{{C}_{6}}{{H}_{5}}N{{O}_{2}},\,{{C}_{6}}{{H}_{6}}\]

    Correct Answer: C

    Solution :

               \[{{C}_{6}}{{H}_{5}}N{{H}_{2}}\underset{{{0}^{o}}C-{{5}^{o}}C}{\mathop{\xrightarrow{NaN{{O}_{2}}/HCl}}}\,\underset{\text{(X)}}{\mathop{{{C}_{6}}{{H}_{5}}N_{2}^{+}C{{l}^{-}}}}\,\underset{{{H}_{2}}O}{\mathop{\xrightarrow{HN{{O}_{2}}}}}\,\]\[\underset{\text{(Y)}}{\mathop{{{C}_{6}}{{H}_{5}}N{{O}_{2}}}}\,+{{N}_{2}}+HCl\]

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