A) \[C{{H}_{3}}Br\]
B) \[C{{H}_{4}}\]
C) \[C{{H}_{3}}COBr\]
D) \[C{{H}_{3}}N{{H}_{2}}\]
Correct Answer: D
Solution :
\[C{{H}_{3}}CON{{H}_{2}}\xrightarrow{NaOBr}C{{H}_{3}}N{{H}_{2}}\].
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