A) Toluene
B) Benzene
C) Aniline
D) Azobenzene
Correct Answer: C
Solution :
\[\underset{\text{Nitrobenzene}}{\mathop{{{C}_{6}}{{H}_{5}}N{{O}_{2}}+6H}}\,\xrightarrow{\text{pt}/{{H}_{2}}}\underset{\text{Aniline}}{\mathop{{{C}_{6}}{{H}_{5}}N{{H}_{2}}}}\,+2{{H}_{2}}O\]
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