A) \[C{{H}_{3}}-C{{H}_{2}}-Br\]
B) \[C{{H}_{3}}-C{{H}_{2}}-N{{H}_{2}}\]
C)
D) \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-N{{H}_{2}}\]
Correct Answer: B
Solution :
\[C{{H}_{3}}C{{H}_{2}}COOH\xrightarrow{SOC{{l}_{2}}}C{{H}_{3}}C{{H}_{2}}COCl+S{{O}_{2}}+HCl\] \[C{{H}_{3}}C{{H}_{2}}COCl+N{{H}_{3}}\to C{{H}_{3}}C{{H}_{2}}CON{{H}_{2}}+HCl\] \[C{{H}_{3}}C{{H}_{2}}CON{{H}_{2}}+B{{r}_{2}}/NaOH\to \underset{\text{Ethyl}\,\,\text{amine}}{\mathop{C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}}}\,+C{{O}_{2}}\]
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