JEE Main & Advanced Chemistry Nitrogen Containing Compounds Question Bank Preparation of Nitrogen Containing Compounds

  • question_answer Starting from propanoic acid, the following reactions were carried out \[\text{Propanoic acid }\xrightarrow{SOC{{l}_{2}}}X\xrightarrow{N{{H}_{3}}}Y\xrightarrow{B{{r}_{2}}+KOH}Z\]  What is the compound Z

    A)                 \[C{{H}_{3}}-C{{H}_{2}}-Br\]

    B)                 \[C{{H}_{3}}-C{{H}_{2}}-N{{H}_{2}}\]

    C)                

    D)                 \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-N{{H}_{2}}\]

    Correct Answer: B

    Solution :

               \[C{{H}_{3}}C{{H}_{2}}COOH\xrightarrow{SOC{{l}_{2}}}C{{H}_{3}}C{{H}_{2}}COCl+S{{O}_{2}}+HCl\]                    \[C{{H}_{3}}C{{H}_{2}}COCl+N{{H}_{3}}\to C{{H}_{3}}C{{H}_{2}}CON{{H}_{2}}+HCl\]                                 \[C{{H}_{3}}C{{H}_{2}}CON{{H}_{2}}+B{{r}_{2}}/NaOH\to \underset{\text{Ethyl}\,\,\text{amine}}{\mathop{C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}}}\,+C{{O}_{2}}\]


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