A) \[RX+N{{H}_{3}}\xrightarrow{{}}\]
B) \[RCH=NOH+[H]\underset{{{C}_{2}}{{H}_{5}}OH}{\mathop{\xrightarrow{Na}}}\,\]
C) \[RCN+{{H}_{2}}O\xrightarrow{{{H}^{+}}}\]
D) \[RCON{{H}_{2}}+4H\xrightarrow{LiAl{{H}_{4}}}\]
Correct Answer: C
Solution :
\[R-CN+{{H}_{2}}O\xrightarrow{{{H}_{2}}O/{{H}^{+}}}RCOOH+N{{H}_{3}}\] It yield amine when reduced as ? \[R-CN+{{H}_{2}}\to R-C{{H}_{2}}-N{{H}_{2}}\]
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