A) \[ROH+SOC{{l}_{2}}\xrightarrow{\ \ \ \ \ \ \ \ \ }\]
B) \[ROH+PC{{l}_{5}}\xrightarrow{\ \ \ \ \ \ \ \ \ \ \ \ }\]
C) \[ROH+PC{{l}_{3}}\xrightarrow{\ \ \ \ \ \ \ \ \ \ \ \ }\]
D) \[ROH+HCl\xrightarrow{\text{anhy}\text{. }ZnC{{l}_{2}}}\]
Correct Answer: A
Solution :
The chlorination of alcohol by \[SOC{{l}_{2}}\] (thionyl chloride) is the best method for the preparation of alkyl halides as in this method all the other product are gaseous and thus halides are obtained on quite pure state \[R-OH+SOC{{l}_{2}}\xrightarrow{\Delta }R-Cl+HCl\uparrow +S{{O}_{2}}\uparrow \]
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