A) Ethyl chloride
B) Chloroform
C) Acetaldehyde
D) Chloral
Correct Answer: D
Solution :
\[C{{H}_{3}}C{{H}_{2}}OH+C{{l}_{2}}\to C{{H}_{3}}CHO+2HCl\] \[C{{H}_{3}}CHO+3C{{l}_{2}}\to \underset{\text{Chloral}}{\mathop{CC{{l}_{3}}\,CHO}}\,+3HCl\]
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