A) \[Ca{{(OH)}_{2}}\]
B) \[C{{l}_{2}}\]
C) Both A and B
D) None of these
Correct Answer: C
Solution :
\[\underset{\text{Bleaching}\,\text{powder}}{\mathop{CaOC{{l}_{2}}+{{H}_{2}}O}}\,\to Ca{{(OH)}_{2}}+C{{l}_{2}}\]
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