A) \[C{{H}_{3}}C{{H}_{2}}Cl\]
B) \[C{{H}_{3}}CHC{{l}_{2}}\]
C) \[CHCl=CHCl\]
D) \[C{{H}_{2}}=CHCl\]
Correct Answer: B
Solution :
\[CH\equiv CH+HCl\to C{{H}_{2}}=CHCl\xrightarrow{+HCl}C{{H}_{3}}CHC{{l}_{2}}\]
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