question_answer

\[C{{H}_{2}}=C{{H}_{2}}+{{B}_{2}}{{H}_{6}}\]\[\underset{{{H}_{2}}S{{O}_{4}}}{\mathop{\xrightarrow{NaOH}}}\,\ \text{Product}\text{.}\] Product in above reaction is                                        [RPMT 2003]

A)                 \[C{{H}_{3}}C{{H}_{2}}CHO\]     

B)                 \[C{{H}_{3}}C{{H}_{2}}OH\]

C)                 \[C{{H}_{3}}CHO\]          

D)                 None of these