A) \[F{{e}^{2+}}\]
B) \[N{{i}^{2+}}\]
C) \[C{{o}^{2+}}\]
D) \[M{{n}^{2+}}\]
Correct Answer: D
Solution :
As \[M{{n}^{+2}}\]has all it?s electrons (5) unpaired in it?s d-orbital, so it?s extra stable configuration requires high excitation energy and so it gives violet colour.
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