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7th Class Mathematics Practical Geometry Question Bank Practical Geometry

  • question_answer
    In the given figure, find the measure of\[\angle ROT,\] if  \[PQ=QR\] and \[\angle QPR={{60}^{o}}\].                                

    A)  \[{{60}^{o}}\]                   

    B)         \[{{140}^{o}}\]

    C)  \[{{120}^{o}}\]                  

    D)         \[{{100}^{o}}\]

    Correct Answer: C

    Solution :

      \[\Delta PQR\] is isosceles since \[PQ=QR\]. \[\therefore \]  \[\angle QPR=\angle QRP={{60}^{o}}\] \[\angle RQT\] is the exterior angle of \[\Delta PQR\] which is equal to the sum of interior opposite angles \[\angle P\] and \[\angle R\]. Hence, \[\angle RQT={{60}^{o}}+{{60}^{o}}={{120}^{o}}\].


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