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9th Class Mathematics Polynomials Question Bank Polynomials

  • question_answer
    If \[{{\left( \mathbf{3a+1} \right)}^{\mathbf{2}}}\mathbf{+}{{\left( \mathbf{b-1} \right)}^{\mathbf{2}}}\mathbf{+}{{\left( \mathbf{2c-3} \right)}^{\mathbf{2}}}\mathbf{=0,}\] than value of \[\left( \mathbf{3a+b+2c} \right)\]is equal to:  

    A)  3    

    B)  -1

    C)  2                                

    D)  5

    Correct Answer: A

    Solution :

    (a): \[{{\left( 3a+1 \right)}^{2}}+{{\left( b-1 \right)}^{2}}-{{\left( 2c-3 \right)}^{2}}=0\] \[\Rightarrow 3a+1=0\Rightarrow 3a=-1\] \[\Rightarrow b-1=0\Rightarrow b=1\] \[\Rightarrow 2c-3=0\] \[\therefore 2c=3\] \[\therefore 3a+b+2c=-1+1+3=3\]                                


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